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15x^2+17x=12
We move all terms to the left:
15x^2+17x-(12)=0
a = 15; b = 17; c = -12;
Δ = b2-4ac
Δ = 172-4·15·(-12)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1009}}{2*15}=\frac{-17-\sqrt{1009}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1009}}{2*15}=\frac{-17+\sqrt{1009}}{30} $
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